Seattle Seahawks, Jamal Adams agree to 4-year, $70 million extension

The Seattle Seahawks have agreed to a four-year extension with Jamal Adams that will make him the NFL's highest-paid safety with a deal that has a maximum value of $72 million, a source told ESPN's Adam Schefter on Tuesday.

The deal for Adams, 25, includes a $20 million signing bonus, a source told Schefter.

It tops the $15.25 million per-year average by the Denver Broncos' Justin Simmons.

The Seahawks and Adams' agent began negotiating early in the offseason and continued to do so through the start of training camp until their recent period of inaction.