Shubhankar Sharma zooms to World No. 72 after title win

Press Trust of India  |  New Delhi 

today emerged as the best Indian in the world, grabbing the 72nd position in the Official World Ranking (OWGR) after his recent title triumph at Championship. Sharma has enjoyed a golden run over the past few months on the international stage, clinching his first win at the Joburg Open in December last year. He had entered the event in ranked 462 in the world and his victory soon catapulted him to 226.

The win in yesterday elevated Sharma from 193 to 72, a gain of 121 spots. Sharma, who stays in Chandigarh and has his roots in Jammu, has broken into the top-100 for the first time in his career and also emerged as the highest ranked Indian in the world surpassing regular Anirban Lahiri, who is currently placed 76th in the OWGR. The 21-year-old Indian now also has the rare distinction of leading both Race to and the Asian Tour Order of Merit. His latest success also helped him join the exclusive who have achieved two wins in the same season, the others being Jeev (2006) and (2015). The race to represent at the 2020 Tokyo just got a lot more intense as there are now five Indians in the top-200 of the world. With two and a half years still to go to the next Olympics, an interesting contest might ensue for the two berths on the Indian team as the likes of Sharma (72), Lahiri (76), Gaganjeet Bhullar (155), Shiv Kapur (192), Ajeetesh Sandhu (199) and SSP Chawrasia (226), are all in the fray at the moment.

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First Published: Mon, February 05 2018. 21:20 IST